PDA for L = a^n b^n | Pushdown Automata for a^n b^n | Automata Theory | TOC
Автор: TopGATE
Загружено: 2023-03-30
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We can design a pushdown automaton (PDA) to recognize the language L = (a^n b^n / n is greater than or equal to 1) as follows:
The PDA will have a single stack symbol Z0 at the bottom of the stack, which represents the start of the stack.
For each input symbol a, the PDA will push an 'a' onto the stack.
For each input symbol b, the PDA will pop an 'b' from the stack.
If the PDA reads the end-of-string marker and the stack contains only the symbol Z0, then the input string is accepted.
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