Leaders in Array | DSA for Beginners | Hinglish Explanation
Автор: Null Pointer Academy
Загружено: 2026-01-08
Просмотров: 110
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Welcome to NullPointer Academy! 🚀
Yeh hai hamari DSA Playlist ka Beesva (Day 20) video. Aaj hum solve karenge Leaders in Array problem — jo interviews aur coding rounds mein kaafi frequently poochha jaata hai.
🔹 Problem Covered:
Array ke leaders find karne hain.
👉 Leader woh element hota hai jo apne right side ke sabhi elements se bada ya barabar ho.
👉 Rightmost element hamesha leader hota hai.
🔹 Language: Hinglish (Simple, clear aur beginner-friendly)
📌 What you’ll learn in this video:
✔ Brute Force Approach –
Har element ke right side ke saare elements check karna using two nested loops.
Time Complexity: O(N²)
Kyun ye approach slow aur inefficient ho jaati hai for large arrays.
✔ Optimal Approach (O(N) Time, O(1) Space) –
Right se left traverse karna
Ek variable mein rightMax maintain karna
Agar current element ≥ rightMax → leader hai
rightMax ko update karna
✔ Dry Run with Examples –
Arrays jaise:
[16, 17, 4, 3, 5, 2]
[1, 2, 3, 4, 0]
Step-by-step explanation ke saath clear intuition.
✔ Full C++ Code Implementation –
Brute force aur optimal dono solutions ka line-by-line explanation.
✔ Time & Space Complexity Analysis –
Brute force vs optimal approach ka proper comparison.
✔ Intuition Behind the Solution –
Kyuni right se traverse karna aur rightMax maintain karna problem ko single pass mein solve kar deta hai.
✔ Interview Insights –
Common mistakes (left se traverse karna, extra space use karna)
Edge cases jaise single element array, strictly increasing/decreasing arrays.
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/ @nullpointeracademy
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Koi doubt ho to comment mein poochho — main reply karke help kar dunga! 🚀
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