Day 11: Binary Search (LeetCode 704) - Fast Search in Sorted Array (O(log n))

Описание: 🎯 Day 11 of My LeetCode Journey | Binary Search (LeetCode 704)

In this video, I solve LeetCode Problem #704 - Binary Search. This is a must-know interview pattern for searching in a sorted array efficiently using O(log n) time.

🔗 Problem Link: https://leetcode.com/problems/binary-...

📌 PROBLEM SUMMARY:
Given a sorted array nums and an integer target, return the index of target if it exists. Otherwise, return -1.
You must solve it in O(log n) runtime.

Example 1:
Input: nums = [-1,0,3,5,9,12], target = 9
Output: 4

Example 2:
Input: nums = [-1,0,3,5,9,12], target = 2
Output: -1

💡 KEY CONCEPTS:
✅ Binary Search Pattern
✅ Two Pointers (low/high)
✅ Mid computation & boundary handling
✅ O(log n) time complexity

📊 COMPLEXITY:
• Time: O(log n)
• Space: O(1) iterative

🎓 DIFFICULTY: Easy
🏷️ TOPICS: Array, Binary Search

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