Container With Most Water - LeetCode 11 | Two Pointers Explained | Day 12 of My LeetCode Journey

Описание: 🎯 Day 12 of My LeetCode Journey | Container With Most Water (LeetCode 11)

In this video, I solve LeetCode Problem #11 - Container With Most Water. This is a classic Two Pointers problem where we find the maximum area formed between two vertical lines in O(n) time.

🔗 Problem Link: https://leetcode.com/problems/contain...

📌 PROBLEM SUMMARY:
You are given an integer array height where each element represents a vertical line at index i.
Find two lines that form a container with the x-axis such that it holds the MOST water.
Return the maximum amount of water. (You cannot slant the container.)

Example 1:
Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49

Example 2:
Input: height = [1,1]
Output: 1

💡 KEY INSIGHT (Two Pointers):
Start with pointers at both ends.
Area = (right - left) * min(height[left], height[right])
Move the pointer with the smaller height inward to potentially find a better container.


📊 COMPLEXITY:
• Time: O(n)
• Space: O(1)

🎓 DIFFICULTY: Medium
🏷️ TOPICS: Array, Two Pointers

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