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The Laplace Transform of Derivatives and Integrals

Автор: Dr. Trefor Bazett

Загружено: 2020-03-18

Просмотров: 163160

Описание: In this video we take the Laplace Transform of derivatives or integrals. What's amazing is that these result in expressions entirely in terms of the original function. This will be important for us when we take the Laplace Transform of a differential equation because it will convert an ODE with initial conditions into an algebraic equation we can hopefully solve more easily.

Formulas:
1) L{f(t)}=sF(s)-f(0)
2)L{ integral from 0 to t of f(tau)} = F(s)/s

This is part of my series on the Laplace Transforms in my Differential Equations Playlist:    • Laplace Transforms and Solving ODEs  

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COURSE PLAYLISTS:
►DISCRETE MATH:    • Discrete Math (Full Course: Sets, Logic, P...  
►LINEAR ALGEBRA:    • Linear Algebra (Full Course)  
►CALCULUS I:    • Calculus I (Limits, Derivative, Integrals)...  
►CALCULUS II:    • Calculus II (Integration Methods, Series, ...  
►MULTIVARIABLE CALCULUS (Calc III):    • Calculus III: Multivariable Calculus (Vect...  
►VECTOR CALCULUS (Calc IV):    • Calculus IV: Vector Calculus (Line Integra...  
►DIFFERENTIAL EQUATIONS:    • Ordinary Differential Equations (ODEs)  
►LAPLACE TRANSFORM:    • Laplace Transforms and Solving ODEs  
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OTHER PLAYLISTS:
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The Laplace Transform of Derivatives and Integrals

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