Redox reaction balancing by oxidation number method

Описание: Redox reaction balancing by oxidation number method (‪@RasayanSutra‬ )
Most of the student facing some problem during studding redox balance topic as some time in examination it is asked balance in acid medium or basic medium, book are full of vast rule which is hard to understand. So I will explain in simple steps to easy to understand.
concept:
step-1: identify the reduction half cell and oxidation half cell
step-2: break the half cell
step-3: balance the element other than H and O
step-4: balance the O using water
step-5: balance the H using H+
step-6: balance the charge using electron in excess positive side of half cell
step-7: sum both the half cell and eliminate charge
this balancing will be in acid medium.
To balance in base medium add both side OH- and remove water.
practice:
Practice Set: Redox Reaction Balancing
Acidic Medium
MnO4⁻ + Fe²⁺ → Mn²⁺ + Fe³⁺
Cr2O7²⁻ + SO2 → Cr³⁺ + SO4²⁻
MnO4⁻ + C2O4²⁻ → Mn²⁺ + CO2
Cu + HNO3 → Cu²⁺ + NO + H2O
Basic Medium
Cl2 + OH⁻ → Cl⁻ + ClO⁻
H2O2 + OCl⁻ → Cl⁻ + O2 + H2O
I2 + OH⁻ → IO3⁻ + I⁻ + H2O
Disproportionation- H2O2 → O2 + H2O
Cl2 + OH⁻ → Cl⁻ + ClO⁻
NO2⁻ → NO3⁻ + NO
Simple Metal Reactions- Zn + H⁺ → Zn²⁺ + H2
Fe²⁺ + I2 → Fe³⁺ + I⁻
Sn²⁺ + HgCl2 → Sn⁴⁺ + Hg
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#bengali #redoxreaction #balancingchemicalequations