algebra problem! Given a + b = 7 and ab = 10, can we find the value of a^2 + b^2 + 3ab?
Автор: Pashtoon talented education
Загружено: 2025-12-05
Просмотров: 4
Описание:
Let's break this down. We know a + b = 7 and ab = 10.
We can square the first equation: (a + b)^2 = 49
This gives us: a^2 + 2ab + b^2 = 49
Since ab = 10, we have: a^2 + 2(10) + b^2 = 49
a^2 + b^2 + 20 = 49
a^2 + b^2 = 29
Now we add 3ab:
a^2 + b^2 + 3ab = 29 + 3(10)
= 29 + 30
= 59
So a^2 + b^2 + 3ab = 59
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