LeetCode 1784 | Check if Binary String Has At Most One Segment of Ones | Logic Explained in 2 min
Автор: Qubit Coderz
Загружено: 2026-03-06
Просмотров: 8
Описание:
Check if Binary String Has At Most One Segment of Ones | LeetCode 1784 | C++ Solution
In this video, we solve LeetCode 1784 – "Check if Binary String Has At Most One Segment of Ones." The problem asks us to determine whether a binary string contains at most one continuous segment of `1`s.
We go through the intuition, logic, and an efficient implementation in C++ to solve this problem.
🔹 Key Idea
A valid binary string can contain only one block of `1`s. Once we encounter a `1` after a sequence of `0`(s), it will start a second substring of '1'. If it happens, the string contains more than one segment of ones.
Examples:
✅ `1111000` → Valid (one segment of `1`s)
✅ `1` → Valid
❌ `101` → Invalid (two segments of `1`s)
❌ `110011` → Invalid
🔹 *Complexity*
*Time Complexity:* O(n)
*Space Complexity:* O(1)
💻 *Language Used:* *C++*
If you found this helpful, make sure to like the video and subscribe for more LeetCode solutions, DSA explanations, and coding interview preparation content.
#leetcode #cpp #dsa #codinginterview #algorithms #programming
Повторяем попытку...
Доступные форматы для скачивания:
Скачать видео
-
Информация по загрузке:
![Best of Deep House [2026] | Melodic House & Progressive Flow](https://imager.clipsaver.ru/Il-ZpBuC8tA/max.jpg)
