LeetCode 110 | Balanced Binary Tree 🔥 | One-Pass DFS Explained | O(n) Solution
Автор: codeWithKhan
Загружено: 2026-02-07
Просмотров: 16
Описание:
In this video, we solve LeetCode 110 – Balanced Binary Tree using an efficient one-pass DFS approach 🚀
A binary tree is considered height-balanced if, for every node, the height difference between its left and right subtree is at most 1.
💡 Key Highlights:
• Bottom-up DFS strategy ✅
• Using -1 to detect imbalance early
• Clean and optimized Java solution
⏱ Time Complexity: O(n)
📦 Space Complexity: O(h) (recursion stack)
Solution: https://leetcode.com/problems/balance...
This problem is perfect for understanding tree recursion, height calculation, and DFS optimization — a must-know concept for coding interviews!
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