LeetCode Problem 11: Container With Most Water | Two-Pointer C# Solution Explained

Описание: Here's my solution to the LeetCode Problem 11: Container With Most Water, implemented in C# using an Efficient Two-Pointer Technique. 🚀

💡 Problem Overview:
The challenge is to find two lines in the given array height that, together with the x-axis, form a container that can store the most water. This solution uses the two-pointer approach to efficiently calculate the maximum area.

✅ What You'll Learn in This Video:

The Two-Pointer Technique to optimize the process of solving problems with arrays efficiently.
How to calculate the area of water between two indices.
A simple yet highly optimized C# solution to find the container with the most water.
🔔 Code Highlights:

Time Complexity: O(n), where n is the length of the array. The two-pointer approach ensures we're only traversing the array once.
Space Complexity: O(1), as the solution works in place using only two pointers and a variable to store the maximum area.
Core Insight: Start with two pointers at both ends of the array and calculate the area. Then, move the smaller height pointer inward to find potentially larger areas while keeping the other pointer fixed. This strategy ensures optimal performance without needing nested loops.
💡 This problem introduces the two-pointer strategy, making it a great example of optimizing solutions for array-based problems and subarray calculations. It's a must-know concept for competitive programming and coding interviews.

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