How to find the Oxidation Number for N in N2O4 (Dinitrogen tetroxide)
Автор: Wayne Breslyn (Dr. B.)
Загружено: 2018-07-09
Просмотров: 32314
Описание:
To find the oxidation numbers for N2O4 (Dinitrogen tetroxide), and each element in molecule, we use few simple rules and some simple math.
First, since the N2O4 molecule doesn’t have an overall charge (like NO3- or H3O+) we could say that the total of the oxidation numbers for N2O4 will be zero since it is a neutral molecule.
We write the oxidation number (O.N.) for elements that we know and use these to figure out oxidation number for N.
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GENERAL RULES
In a natural atom all O.N. must add up to zero.
Group 1 = +1
Group 2 = +2
Hydrogen with Non-Metals = +1
Hydrogen with Metals (or Boron) = -1
Fluorine = -1
Oxygen = -2 (except in H2O2 or with Fluorine)
Group 17(7A) = -1 except with Oxygen and other halogens lower in the group
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We know that Oxygen usually is -2 with a few exceptions. When Oxygen is in a peroxide, like H2O2 (Hydrogen peroxide), it has a charge of -1. When it is bonded to Fluorine (F) it has an oxidation number of +2.
Here it is bonded to element symbol so the oxidation number on Oxygen is -2. Using this information we can figure out the oxidation number for the element N in N2O4.
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