How to Solve x^x = 7^(x+49) | THE SMART WAY
Автор: Bahula Clinton
Загружено: 2026-01-22
Просмотров: 8
Описание:
In this lesson, we tackle a high-level exponential equation: x^x = 7^(x+49). While it looks intimidating at first glance, this tutorial solves the problem by using a SMART WAY to manipulate the bases and exponents until they match perfectly.
We break this down into STEP-BY-STEP logic that even the most struggling learner can follow:
Step 1: Use exponent laws to split the right side into 7^x * 7^49.
Step 2: Use the inverse operation of multiplication (division) to group the terms with x on one side.
Step 3: Rewrite the equation into the form u^u = k^k to find the value of x effortlessly.
If you have ever felt lost when an exponent contains a variable and a constant, this walkthrough is for you. We show every single operation clearly—leaving no step assumed—to ensure that every matric student in Mzansi can secure these marks. This is the "2in1 Maths Plug" approach to making complex algebra CRYSTAL CLEAR.
Equations used in this video:
Initial Equation: x^x = 7^(x + 49)
Division Step: (x/7)^x = 7^49
Final Solution: x = 49
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