Leetcode 1653

Описание: In this video, we solve the “Minimum Deletions to Make String Balanced” problem using an efficient O(n) greedy approach.

We’ll walk through:
The corrected Python implementation
The intuition behind the algorithm
A clear explanation using counters instead of brute force
Time and space complexity analysis

Problem Overview
A string is considered balanced if all 'a' characters appear before all 'b' characters.

Goal:
Find the minimum number of deletions required to make the string balanced.

Key Idea

At every position in the string:
Count how many 'b' characters are on the left
Count how many 'a' characters are on the right
The sum of these tells us how many deletions are needed at that split point
We compute this efficiently in one pass.

Example Walkthrough

Input:
s = "aababbab"

Total 'a' count = 4
Track deletions needed at each index
Minimum deletions required = 2

Complexity Analysis
Metric Complexity
Time O(n)
Space O(1)
🔥 Why This Approach?

No extra arrays
No nested loops
Works perfectly for large inputs
Ideal for interviews and competitive programming

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