Remainder Trick: 70×71×...×79 ÷ 1000 | Fast Number System Shortcut for SSC & Govt Exams!

Описание: Are you stuck on how to find the remainder of large number products? 🤯
This video will teach you a powerful and easy trick to solve one of the most commonly asked questions in Number System—especially for SSC and other competitive exams.

🧩 Problem Covered in this Video:

Find the remainder when the product 70 × 71 × 72 × ... × 79 is divided by 1000.

At first glance, this looks like a time-consuming multiplication problem... But in this video, we’ll show you how to crack it in under 2 minutes using a smart trick based on modulo arithmetic and last three digits technique!

🎯 What You Will Learn:

🔹 The concept of modulo 1000 and how to break it into modulo 8 and modulo 125 using Chinese Remainder Theorem
🔹 Why multiplying large numbers directly is a trap in exams
🔹 How to apply remainders of consecutive products cleverly
🔹 A unique trick that avoids unnecessary multiplication
🔹 A pattern-based approach that works for similar problems (like 91×92×...×100, etc.)

This method is especially useful for SSC CGL, CHSL, Railway (RRB), IBPS, Group D, NDA, CDS, and other aptitude-based exams where speed and accuracy matter most.

📈 Why This Video is a Must-Watch:

✅ Simple explanation using real logic, no mugging up formulas
✅ Step-by-step breakdown for beginners and revision for pros
✅ Based on actual exam-level questions
✅ Helps build confidence for tricky number system problems
✅ Prepares you for surprises in Tier 1 & Tier 2 math sections

Whether you're a beginner or an advanced learner, you'll walk away with a sharp and time-saving method to tackle remainder problems confidently in the exam.


🎓 Bonus Tips Shared in Video:

How to reduce calculations smartly using Euler’s Theorem & Modular Inverses (in simple terms)

When to split 1000 into 8 and 125 — and how to easily merge the answers using the CRT (Chinese Remainder Theorem)

Memory hacks to retain this method for exam day

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