40. A nucleus of carbon-10 decays by beta-emission to form a nucleus of boron-10. For this decay
Автор: IB Physics Hub | Quick Solve MCQs By Dr. Rao
Загружено: 2024-12-31
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Описание:
A nucleus of carbon-10 decays by beta-emission to form a nucleus of boron-10. For this decay process, what is the change to a nucleon and what is the change in the quark composition of the nucleon?
(March 2024, Paper 12, AS Level)
Solution:
Beta-minus Decay Process (β⁻):
In beta-minus decay, a neutron changes into a proton.
A beta-particle (electron, e⁻) and an antineutrino (ν̅) are emitted.
Symbolically:
n → p + e⁻ + ν̅
Quark Composition Change:
A neutron consists of up-down-down (udd) quarks.
A proton consists of up-up-down (uud) quarks.
The beta-minus decay process involves one down quark becoming an up quark.
Summary of Changes:
Change to nucleon: Neutron changes to proton.
Change in quark composition: One down quark becomes an up quark.
Correct Option:
Option D: Neutron to proton, up becomes down (matches beta-minus decay).
Final Answer:
Option D
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