Class 10 Maths | Chapter 10 Circle | Exercise 10.2 Full Explanation | NCERT Solution

Описание: Class 10 Maths | Chapter 10 Circle | Exercise 10.2 Full Explanation | NCERT Solution

Class 10 Maths – Chapter 10 (Circle) ka Exercise 10.2 yahan full explanation ke saath solve kiya gaya hai.
Is video mein aap concept, theorem aur NCERT ke important questions ko simple aur easy language me samjhoge.

👉 Topics Covered:
✔ What is Circle?
✔ Important Theorems of Circle
✔ Ex 10.2 Complete Solutions
✔ Easy Diagram Explanation
✔ NCERT Based Questions

🔥Timestamps: 🔥

00:00 – Introduction

00:45 – Q1.) From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is

03:57 – Q2.) In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that ∠POQ = 110°, then ∠PTQ is equal to ______.

06:58 – Q3.) If tangents PA and PB from a point P to a circle with centre O are inclined to each other at an angle of 80°, then ∠POA is equal to ______.

10:02 – Q4.) Prove that the tangents drawn at the ends of a diameter of a circle are parallel.

13:34 – Q5.) Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.

10:07 – Q6.) The length of a tangent from a point A at distance 5 cm from the centre of the circle is 4 cm. Find the radius of the circle.

21:48 – Q7.) Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.

27:57 – Q8.) A quadrilateral ABCD is drawn to circumscribe a circle (see Fig. 10.12). Prove that AB + CD = AD + BC

31:32 – Q9.) In Fig. 10.13, XY and X'Y' are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and X'Y' at B.
Prove that ∠AOB = 90°.

37:35 – Q10.) Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre.

42:13 – Q11.) Prove that the parallelogram circumscribing a circle is a rhombus.

48:00 – Q12.) A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC into which BC is divided by the point of contact D are of lengths 8 cm and 6 cm respectively (see Fig. 10.14). Find the sides AB and AC

01:04:17 – Q13.) Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.


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CBSE | State Board | Class 10 | NCERT Students

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