Find Error in K.E = p² / 2m | Short Trick for JEE NEET Physics

Описание: Welcome to SCC Simplify Physics by Shinde Sir

In this conceptual trick video, we solve a percentage error question based on Kinetic Energy using momentum:


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📘 Formula Used:

K.E = \frac{p^2}{2m}


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🧠 Error Propagation Rule:

\frac{\Delta K.E}{K.E} = 2 \cdot \frac{\Delta p}{p} + \frac{\Delta m}{m}


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📐 Given Data:

Percentage error in momentum = 2%

Percentage error in mass = 1%



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📊 Apply the Formula:

\frac{\Delta K.E}{K.E} = 2 \cdot 2 + 1 = \boxed{5\%}

✅ Final Answer: 5%


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📌 Helpful For:

JEE Main & Advanced

NEET Physics

CET, CBSE, HSC

Class 11 – Units & Measurements



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📲 Join Telegram for Notes + DPPs
https://t.me/physicseasyheinn

📥 Download PDFs:
JEE PYQs → https://bit.ly/4febevZ
NEET DPPs → https://bit.ly/46yfapk
CET Physics → https://bit.ly/3IJlYXh

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