Ex 6.3 Question 9 | ΔABC & ΔAMP Similar Proof | CA/PA = BC/MP | Class 10 NCERT Triangles

Описание: In this video, I have solved Exercise 6.3 Question 9 of Class 10 Maths (NCERT), Chapter 6 – Triangles. This question involves proving the similarity of two right-angled triangles and establishing a proportionality relation between their corresponding sides. I have explained each step in the easiest and most conceptual way for quick understanding.

📘 NCERT Exercise 6.3 – Question 9 (Exact Question)

👉 Q9. In the following figure, ∆ABC and ∆AMP are right-angled at B and M respectively. Prove that:

(i) ∆ABC ~ ∆AMP
(ii) 𝐶𝐴/𝑃𝐴=𝐵𝐶/𝑀𝑃
or
AC/AP= BC/MP


🔍 What you will learn (other than the NCERT question):

• How to identify right-angled triangles for similarity

• Using angle-angle (AA) similarity condition

• How to compare corresponding sides

• How to write correct similarity statements

• Geometry logic behind proportional sides

• Step-by-step method to prove two triangles are similar


🎯 Who should watch this video?

This video is useful for:
• Class 9 and Class 10 students

• Class 10 Board exam students

• Students who love geometry, especially triangles

• Students preparing for competitive exams like SSC, Railway, Bank PO, Police, and other government job exams, where geometry questions are frequently asked


🧠 Topics Covered:

• Similar Triangles

• AA Similarity

• Proportional Sides
• Geometry Proofs

• NCERT Chapter 6 Triangles

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More Class 10 Maths solutions coming soon.



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