Class 9 Maths Exercise 6.2 | Lines & Angles का सबसे आसान समाधान | Lecture 5 (Full Explanation)”

Описание: Lecture 5 me hum NCERT Class 9 Maths – Chapter 6 (Lines and Angles) ki Exercise 6.2 complete solve karenge.
Is exercise me mainly concepts cover hote हैं:
✔ Vertically Opposite Angles
✔ Linear Pair
✔ Adjacent Angles
✔ Angle Sum Concepts
✔ Intersecting Lines Geometry

Is lecture me har question ko step-by-step reasoning ke saath solve kiya gaya hai, jisse aap exam aur school tests me full marks laa sakte हैं।
Video ke end me Practice ke liye DPP-5 bhi diya hai jo आपकी problem-solving skill को boost kareगा।

👉 Don’t forget to download the DPP and try before watching the solution!
👉 LIKE + SHARE + SUBSCRIBE for more Class 9 Maths Lectures.




#class9maths #linesandangles #exercise6_2 #ncertsolution #cbseclass9 #mathslecture #lineandangle #ferraataphysics #class9chapter6 #ncertclass9maths #geometryclass9 #mathsbylulu




Topic: Based on NCERT Exercise 6.2 + Angle Relation

Q1. Two angles form a linear pair. One angle is 47°. Find the other angle.

Q2. Two lines intersect. One angle is 130°. Find all other three angles.

Q3. In the figure, ∠AOD = 150° and OC is a ray inside ∠AOD. If ∠AOC = 3x° and ∠COD = (x + 30)°, find x.

Q4. If two angles are vertically opposite and one is (5x – 10)°, the other is (3x + 30)°. Find x and both angles.

Q5. ∠1 and ∠2 form a linear pair. If ∠1 = (4y + 5)° and ∠2 = (6y – 25)°, find y.

Q6. A straight line makes two adjacent angles ∠A = (3x + 20)° and ∠B = (7x – 40)°. They form a linear pair. Find x and both angles.

Q7. State True/False:

a) Vertically opposite angles are equal.
b) Adjacent angles always form a linear pair.
c) Sum of linear pair is 180°.
d) Vertical angles form at least two pairs.

Q8. One angle is twice its adjacent angle and they form a linear pair. Find both angles.

Q9. If ∠A = 45° and ∠B is its vertically opposite angle, what is ∠B? What are the other two angles formed?

Q10. In ∠AOB, OC is a ray such that ∠AOC = 2x° and ∠COB = (5x – 30)°. If ∠AOB = 150°, find x.