The equation of the directrix of the parabola y^2+4y+4x+2=0 is
Автор: Math Master - Impetus Gurukul
Загружено: 2024-07-04
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The equation of the directrix of the parabola y^2+4y+4x+2=0 is
(A) x=-1 (B) x=1
(C) x=-3/2 (D) x=3/2
(a) 1. B
(b) 2. A
(c) 3. C
(d) 4. D
Ans: d
Sol.
We can write the equation of the given parabola as
(y+2)^2=-4(x-1/2)shifting the origin to (1/2,-2), the equation of parabola becomes Y^2=-4X, where X=x-1/2,Y=y+2
An equation of its directrix is X=1
Hence required directrix is x=3/2
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