From the top of an upright pole 24√𝟑ft high,angle of elevation of top of an upright tower was 60°.
Автор: 1MATH by 1EQ
Загружено: 2024-11-11
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Описание:
From the top of an upright pole 24√𝟑 feet high, the angle of elevation of the top of an upright tower was 60°. If the foot of the pole was 60 feet away from the foot of the tower, what tall (in feet) was the tower?
(a) 84√3(b) 36√3(c) 44√3(d) 60√3
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