Find the last three digits of the floor(10^105/(10^21+5)), Similar to Putnam 1986 problem 2
Автор: My One Fiftieth Of A Dollar
Загружено: 2022-04-17
Просмотров: 236
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This is a variation on problem done by Math Booster on a China Junior Math Olympiad Problem. Determine the last three digits of the floor(10^105/(10^21+5)). MSTang published a similar solution to the Putnam Competition 1986 Problem 2. Sum of two 5th powers factorization was important as well as the floor property which states that the floor of an integer plus a real number is equal to the integer plus the floor of the real number.
Also thanks to informative piece done by Deb Chatigny on scientific notation which really helps when dealing with cumbersome unpronounceable large numbers!
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