Vectors and 3D Geometry Problems Solving - 3 | Class 12 , JEE Maths | Rohit Ranjan (IIT KGP)

Описание: In this video, we solve a Class 12 Vectors & 3D Geometry problem in which the given lines are expressed in 3D Cartesian (symmetric) form, instead of vector form.

👉 Problem Statement
Find the equation of a line passing through the point (1, 2, −4) and perpendicular to both of the following lines:
L1: (x−8)/3 = (y+19)/(−16) = (z−10)/7 and L2: (x−15)/3 = (y−29)/8 = (z−5)/(−5)
🔍 Concepts Used
✔ Direction ratios from symmetric form of a line
✔ Condition for a line to be perpendicular to two given lines
✔ Cross product to obtain a perpendicular direction vector
✔ Equation of a line passing through a given point
✔ Conversion between Cartesian and vector understanding
The problem is solved step by step, with special emphasis on:
Extracting direction ratios correctly


Understanding geometric meaning of perpendicularity


Writing the final equation in a board-exam-friendly format



🎯 Who Should Watch This Video?
Class 12 CBSE / ISC students


Students preparing for school exams


Learners strengthening fundamentals of Vectors & 3D Geometry


This video helps students understand that the method remains the same, whether lines are given in vector form or Cartesian form.

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