Class 9 Maths Final Test Discussion | Linear Equation & Lines and Angles | Infinix Classes

Описание: 📘 Infinix Classes | Maths by Faiz Sir

In this video, Faiz Sir is discussing the Final Part of Class 9 Maths Test covering Linear Equations in Two Variables and Lines and Angles (Advanced Questions).
इस वीडियो में Faiz Sir ने क्लास 9 के Linear Equation in Two Variables और Lines and Angles के फाइनल टेस्ट के एडवांस लेवल प्रश्नों पर विस्तार से चर्चा की है।
यह वीडियो आपके Final Exam Preparation के लिए बहुत ही उपयोगी साबित होगा।
सभी प्रश्नों को step-by-step तरीके से समझाया गया है ताकि concepts पूरी तरह clear हो जाएं।

📚 Questions Discussed in This Video:

12️⃣ If an angle is half of its complement, find the measure of angles.
13️⃣ Two adjacent angles are in the ratio 5:3 and they together form an angle of 128°, find these angles.
14️⃣ If lines AB and CD intersect at F and ∠EFA = ∠AFD, ∠CFB = 50°, find ∠EFC.
15️⃣ If an angle measures 10° more than its complement, then find the measure of the angle.
16️⃣ How many degrees are there in an angle which is one-fifth of its complement?
17️⃣ For what value of x + y will ABC be a line? Justify your answer.
18️⃣ Prove that the sum of the three angles of a triangle is 180°.
19️⃣ In ΔPQR, if PA is bisector of ∠QPR and PM ⊥ QR, prove ∠APM = ½ (∠Q – ∠R).
20️⃣ In ΔABR, DE || QR and AP, BP are bisectors of ∠EAB and ∠RBA respectively. Find ∠APB.

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12) If an angle is half of its complement, find the measure of angles. [2]


13) Two adjacent angles are in the ratio 5 : 3 and they together form an angle of 128°, find these angles. [2]



14) In the given figure, lines AB and CD intersect at F. If ∠EFA = ∠AFD and ∠CFB = 50°, find ∠EFC. [2]



15) If an angle measures 10° more than its complement, then find the measure of the angle? [2]



16) How many degrees are there in an angle which is one-fifth of its complement? [2]



17) For what value of x + y in Fig. will ABC be a line? Justify your answer. [1]


18) Prove that the sum of the three angles of a triangle is 180°. [3]



19) In Fig., ∠Q greater than ∠R, PA is the bisector of ∠QPR and PM ⊥ QR. Prove that ∠APM = 1/2 (∠Q – ∠R). [3]



20) In Fig., DE || QR and AP and BP are bisectors of ∠ EAB and ∠ RBA, respectively. Find ∠APB. [3]