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Lecture 1 | Permutation and Combination Class 11 | Semester 1 |

Автор: Ayan chakraborty classes-Class 11 and 12

Загружено: 2025-04-19

Просмотров: 18816

Описание: Welcome to Lecture 1 of our Class 11 Mathematics series for Semester 1! 📚
In this session, we begin our journey into the world of Permutations and Combinations – a key topic in combinatorics and crucial for board exams, competitive exams, and logical reasoning.

#mathematics #maths #education


✅ What you'll learn in this video:
1.What are permutations and combinations?
2.Real-life examples to understand the difference
3.Basic formulas and logic
4.When to use permutations vs combinations

✨ This is the perfect starting point for students aiming to score high in exams and build a strong foundation in Class 11 Maths.

Why this channel is best Mathematics ❓

1. Conceptual approach updated informative lectures (90% Entrance Coverage).
2. CORRECT INFORMATION PROVIDE + IN-DEPTH KNOWLEDGE + JOIN ENTRANCE QUESTIONS SOLVING.
3. Routine-wise classes uploading.

📌 Don’t forget to Like, Share & Subscribe for more lectures and updates!

🛎️ Stay tuned for Lecture 2 where we dive deeper into Permutations with solved examples!
📌 Watch lectures:
Set theory playlist:
   • Set Theory ( সেট তত্ত্ব )  
Trigonometry Playlist :
   • Trigonometry ( ত্রিকোণমিতি )  
Complex Number :
   • Complex Number (জটিল সংখ্যা )  
PERMUTATION AND COMBINATIONS :
   • PERMUTATION & COMBINATION ( বিন্যাস ও  সমব...  
Relation and Function :
   • Trigonometric Functions of Compound Angles...  
Calculus:
   • Lecture 4 | Limit ( সীমা ) | Important For...  


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Solution:
13:05
Apart from these six types of roads, there’s no other route from the village to abroad.

29:46

( Here, we use addition principle)
Q1). The class teacher can make this selection in (10+5) ways =15 ways. [Option:C]

32:07
(Here, we use addition principle.)
Q2). The person can enter the city in (15+10) ways=25 ways. [Option:C]

36:24
( Here, we use addition principle)
Q3). The total number of possible outfits the boy has (4×3)=12. [Option:D]

39:58
( Here, we use multiplication principle)
Q4). The person can order ice-creams in (6×3) ways=18 ways.
[Option: C]

44:33
(Here, we use multiplication principle.)
***Q5). He(she) can take his(her) lunch in (5×15×3)ways =225 ways. [Option:D]

49:22

*****Q6). The total number of one digit numbers= 3

[since, there is no repetition in digits]

So, the total number of two digits numbers=(3×2)=6

Again, the total number of three digits numbers=(3×2×1)=6

(Here , we use addition principle.)

So, the total number of numbers formed using only the digits 5, 3, and 7 without repetition is: (3+6+6)=15 [Option:A]

Timestamp
0:00 coming up
1:02 intro
1:16 ভোটে তোরাই জিতেছিস
1:49 Problem টা হচ্ছে
2:15 আমার সবথেকে বড়ো problem ছিল
3:56 চ্যাপ্টার টা শিখতে গেলে কী করতে হবে?
4:51 কেন তোদের কথা মানলাম না !
6:00 এটা সবথেকে বড়ো ভুল
8:18 বাসে করে বাংলাদেশ
9:53 Example 1
13:37 Example 2
14:22 10 জন ছেলে এবং 7 জন মেয়ের 😦 মধ্যে একজনই হতে পারবে
22:45 Example 3
24:53 Addition Rule And Multiplication Rule
29:48 MCQ 1
32:04 MCQ 2
36:17 MCQ 3
39:56 MCQ 4
44:32 MCQ 5
49:21 MCQ 6
58:53 দেখো আর শেখো
1:00:05 Outro


🔖 Tags:
#permutationsandcombinations _and_combinations
#permutations and combinations_jee_mains
#permutation_by_ayan_sir
#combinations_by_ayan_sir

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