Leetcode #4: Median Of Two Sorted Arrays

Описание: Conquer LeetCode's Median of Two Sorted Arrays (Problem #4)! 💎
Question Link :- https://leetcode.com/problems/median-...
This is one of the most famous "Hard" problems, demanding an optimal solution with O(log(min(m, n))) time complexity. We'll go from naive approaches to the sophisticated binary search on partitions that will impress any interviewer.

🔍 What We're Solving:Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays. The overall run time complexity should be O(log(m+n)).
🛠️ Approaches Covered:
Brute Force: Merge & Sort (O((m+n)log(m+n)) Time, O(m+n) Space)Simple but too slow. We'll manually copy and sort to understand the baseline.

Merge Step (O(m+n) Time, O(m+n) Space)Build a new sorted array efficiently using two pointers. Better, but still not optimal for space or time complexity constraint.

Optimal Solution: Binary Search on Partitions (O(log(min(m, n))) Time, O(1) Space)The "Hard" solution! This involves finding the perfect "cut" or "partition" in the arrays using binary search, ensuring elements are balanced on both sides and sorted correctly. This is the core logic for the interview.

Repository Link :- https://github.com/TheRecursivePath/L...