The "Power Substitution" Trick for Definite Integrals! ♾️ | Day 13/90 JEE Advanced Masterclass

Описание: How do you simplify an integral that has log e x raised to fractional powers?🧐
In Day 13 of our 90-Day Masterclass, we break down a classic JEE Advanced Calculus problem(2022 Paper 1 Q9 ). Most students get stuck on the $(a - (\log_e x)^{3/2})^2$ term in the denominator, but with the right substitution, it becomes a simple power-rule problem.
Inside this video:
Substitution Masterclass: Why choosing $u = \log_e x$ (or even $u = (\log_e x)^{3/2}$) changes the game.
Boundary Shifts: How to properly change your limits from $x \in [1, e]$ to your new variable.
Evaluating $a$: Solving the final algebraic equation to determine if $a$ is an integer, irrational, or if it even exists.
JEE Trap: Checking the given domain $a \in (-\infty, 0) \cup (1, \infty)$ against your calculated value.

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