Solving Number Theory Problem From NBHM 2023 | Solved with two Methods
Автор: Prime Institute of Mathematics, Amravati
Загружено: 2024-07-30
Просмотров: 252
Описание:
In today's video, we tackle an intriguing number theory problem from NBHM 2023 exam!
Problem: Find all integers m, 2 ≤ m ≤ 999 such that m^2 ≡ m mod 1000
We solve this problem using two distinct approaches:
1. A basic number theory approach.
2. A ring theory approach.
This comprehensive video is perfect for anyone interested in seeing different mathematical techniques in action. Whether you're a student preparing for Mathematics exams like NBHM, TIFR Mathematics, CMI, CSIR NET Mathematics, IIT JAM Mathematics or a math enthusiast, this video will provide valuable insights and methods.
Video Keywords: number theory, numbers, integers, Congruence modulo n, a divides b, Chinese Remainder theorem, ring theory, rings, quotient ring, direct product of rings, Idempotent elements, local rings.
🔔 Don't forget to subscribe and hit the bell icon! to stay updated with our latest videos!
👍 Like, share, and leave your comments below! with your thoughts or any questions you have! Happy Learning!
Follow us on social media for Updates:
🔗 WhatsApp Channel Link:
https://whatsapp.com/channel/0029VaAi...
🔗 Facebook page Link:
https://www.facebook.com/profile.php?...
#mathematics #numbertheory #nbhmphd #nbhm #mathconcepts #numbers #abstractalgebra #ringtheory
#csirnetmathematics #tifrmaths #csirnetmaths
Повторяем попытку...
Доступные форматы для скачивания:
Скачать видео
-
Информация по загрузке: