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How to Use XPath to Locate Nodes with Expressions from Another Node XPath Expression

XPath to find a node by expression specified within another node

xml

xpath

xpath 1.0

Автор: vlogize

Загружено: 2025-09-18

Просмотров: 0

Описание: Learn how to effectively use XPath 1.0 to retrieve node values based on references within another node in XML documents.
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This video is based on the question https://stackoverflow.com/q/62292230/ asked by the user 'SlowFox' ( https://stackoverflow.com/u/12327738/ ) and on the answer https://stackoverflow.com/a/62292439/ provided by the user 'Gilles Quénot' ( https://stackoverflow.com/u/465183/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: XPath to find a node by expression specified within another node

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Unlocking XPath: Finding Nodes with References from Another Node

Navigating XML documents can be quite challenging, especially when you're tasked with extracting specific values that rely on references found in other parts of the document. This situation often arises when dealing with complex XML structures, especially when working on XML mappings. In this post, we'll tackle a common problem involving XPath queries and provide a clear solution.

Problem Overview

Imagine you have an XML document structured with multiple <PARTY> elements and a <PARTIES_REFERENCE> section that identifies which party is responsible for delivery. Here’s a quick look at our example XML:

[[See Video to Reveal this Text or Code Snippet]]

You want to extract the NAME of the delivery address by referencing the DELIVERY_IDREF node, which points to a corresponding PARTY_ID. This needs to be accomplished using a single XPath 1.0 expression. Let’s break down how to create that expression.

Solution: Crafting the XPath Expression

To achieve this, we need to construct an XPath expression that does the following:

Accesses the PARTY elements.

Compares the PARTY_ID in each PARTY against the value found in the DELIVERY_IDREF node.

Retrieves the corresponding NAME element from the ADDRESS sub-node of the matched PARTY.

The XPath expression that fulfills this requirement is as follows:

[[See Video to Reveal this Text or Code Snippet]]

Breakdown of the Expression

/PARTIES: This directs XPath to start looking in the root <PARTIES> node.

/PARTY: Next, we access every <PARTY> element within <PARTIES>.

[./PARTY_ID=/PARTIES/PARTIES_REFERENCE/DELIVERY_IDREF/text()]: This condition filters to find only those <PARTY> elements whose <PARTY_ID> matches the text of the DELIVERY_IDREF element found in <PARTIES_REFERENCE>.

/ADDRESS/NAME/text(): Finally, for the matching <PARTY>, we navigate down to the <ADDRESS> node and then to <NAME> to extract the desired name text.

Conclusion

Using XPath effectively can simplify the process of extracting data from complex XML documents. By leveraging the correct expressions, you can efficiently query and obtain the specific information you need. In this post, we solved a relatively common scenario where nodes are interconnected through references. The approach provided not only addresses the immediate problem but also lays a foundation for future XML queries you may encounter.

With this knowledge, you can tackle XPath challenges with confidence and ensure that your XML data extraction workflows are efficient and reliable!

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How to Use XPath to Locate Nodes with Expressions from Another Node XPath Expression

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