Class 10th Chapter 6 Triangles Example 8 Maths New NCERT CBSE Syllabus | In fig. 6.33 CM and RN are

Описание: Class 10th Chapter 6 Triangles Example 8 Maths New NCERT CBSE Syllabus | In fig. 6.33 CM and RN are

✅️Class 10 Maths Chapter 6 Triangles Full chapter's Playlist NCERT new book Latest Cbse Pattern:    • Class 10 Maths Chapter 6 Triangles Full ch...  

✅️Exercise 6.1    • Class 10th Chapter 6 Triangles Exercise 6....  
✅️Exercise 6.2    • Class 10th Chapter 6 Triangles Full Exerci...  

✅️Exercise 6.3 Q1 to Q10👇    / tujmrlyfch  
✅️Exercise 6.3 Q11 to Q16👇    • Class 10th Maths Triangles Exercise 6.3 (Q...  

✅️Theorem 6.1 BPT Theorem: Basic Proportionality Theorem    • Class 10th Chapter 6 Triangles Theorem 6.1...  
✅️Theorem 6.2 : Converse of BPT    • Class 10th Maths Converse of BPT | Ch-6  T...  

An important Example has been solved here from ncert new Mathematics text book prescribed by cbse board latest syllabus chapter number 6 triangle Example number 8

Example 8 : In Fig. 6.33, CM and RN are
respectively the medians of triangle ABC and
triangle PQR. If Triangle ABC ~ Triangle PQR, prove that :
(i) Triangle AMC ~ Triangle PNR
(ii)CM/RN = AB/PQ
(iii)Triangle CMB ~ Triangle RNQ

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