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DSA in Python Course - Kth Largest Element in an Array | QuickSelect Algorithm | Part 188

Автор: Code and Debug

Загружено: 2025-07-22

Просмотров: 584

Описание: 📘 Welcome to Part 188 of Code & Debug's DSA in Python Course!

Building on your mastery of heap-based algorithms like Heap Sort, we now solve the classic problem: Kth Largest Element in an Array from LeetCode using the powerful QuickSelect Algorithm. We'll implement an efficient randomized approach that finds the kth largest element in O(n) average time complexity, making it more efficient than heap-based solutions for this specific problem.

This session combines partitioning techniques with random pivot selection, demonstrating an optimal approach that's frequently asked in coding interviews at top tech companies!

👨‍🏫 What's covered in this video:
✅ Understanding the problem statement from LeetCode
✅ QuickSelect algorithm vs. other approaches (heap, sorting)
✅ Randomized pivot selection for better performance
✅ Partitioning technique to arrange elements efficiently
✅ Step-by-step Python code walkthrough
✅ Time Complexity: O(n) average, O(n²) worst case analysis
✅ Space Complexity: O(1) in-place solution
✅ Interview tips and optimization strategies

By the end of this session, you'll master QuickSelect and understand how to apply divide-and-conquer techniques for selection problems!

🔗 LeetCode Problem - Kth Largest Element in an Array:
https://leetcode.com/problems/kth-lar...

📄 Full Playlist Sheet (All Questions in Order):
https://docs.google.com/spreadsheets/...

🎓 Enroll in the FREE Python DSA Course:
https://codeanddebug.in/course/master...

🚀 Advance Python DSA for FAANG (Zero to Hero Course):
https://codeanddebug.in/course/zero-t...

Stay focused and keep coding with Code & Debug.
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#KthLargestElement #QuickSelect #LeetCode #PythonDSA #CodeAndDebug #Part188 #DataStructures #PartitionAlgorithm #DivideAndConquer #DSAforInterviews #LeetCodeMedium #SelectionAlgorithm

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DSA in Python Course - Kth Largest Element in an Array | QuickSelect Algorithm | Part 188

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