Find All Factors of a Number in O(√n) | Stop Using O(n) Brute Force!

Описание: Want to find all factors of a number efficiently?

Most beginners check from 1 to n — which takes O(n) time.
But did you know you only need to check till √n?

In this video, we break down:
Brute force approach to find factors (O(n))
Why factors always come in pairs
The key observation behind square root optimization
Optimized O(√n) solution in Java
How to avoid duplicate factors for perfect squares
Time complexity comparison

We’ll walk through a clear example (36) and then implement both brute force and optimized solutions step by step.

This concept is extremely important for:
Prime number checking
Competitive programming
Coding interviews
Number theory basics
DSA beginners

By the end of this video, you’ll clearly understand WHY we check till √n — not just memorize it.

📌 Java Code Covered:

Brute force factor finding
Optimized √n solution
Sorted factor output version

Timestamps:
00:00 Introduction
00:06 The Problem
04:31 Brute Force Approach
05:56 The Problem of O(n) Complexity
10:07 Finding The Pattern
20:15 Optimized Solution Implementation
26:55 End

If you're learning Data Structures & Algorithms from scratch, this series will help you build strong fundamentals.

Subscribe and continue with:
Recursion
Josephus Problem
Bit manipulation
XOR tricks
Mathematical optimizations



#DSA #Java #CodingInterview #NumberTheory #CompetitiveProgramming #LearnToCode #SquareRootOptimization #Programming #FromBruteToBest