why sin(90+θ) = cosθ, cos(90+θ) = -sinθ, tan(90+θ) = -cotθ | Trigonometric Ratios of Allied Angles

Описание: This is the 1st Part of the 4th lecture on Trigonometric Functions of Class 11 Maths NCERT. In this lecture, you will understand the concept of Trigonometric Ratios of allied Angles with the help of a unit circle.

I will show you the derivation that why sin(90+θ) = cosθ, cos(90+θ) = -sinθ, tan(90+θ) = -cotθ, sin(90-θ) = cosθ, cos(90-θ) = sinθ, tan(90-θ) = cotθ.

00:00 First you have to understand the concept of a Unit Circle.
26:12 Derivation of sin(90-θ) = cosθ, cos(90-θ) = sinθ, tan(90-θ) = cotθ
33:52 Derivation of sin(90+θ) = cosθ, cos(90+θ) = -sinθ, tan(90+θ) = -cotθ

Class 11 maths chapter 3 | Allied angles formula | Allied angles class 11 | Trigonometric ratios of allied angles class 11 | Allied angles in Hindi | concept of allied angles | Allied angles in trigonometry class 11| Transformations in trigonometry | Transformations in trigonometric functions | transformations in trig functions | classes by ca devinder singh | Class 11 Maths Ch 3 Trigonometric Functions

why sin(90+θ) = cosθ, cos(90+θ) = -sinθ, tan(90+θ) = -cotθ | Trigonometric Ratios of Allied Angles

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