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How to Create a New Model and Deserialize JSON into It in C#

How to create new model and serialise json into it

c#

Автор: vlogize

Загружено: 2025-03-24

Просмотров: 1

Описание: A comprehensive guide to creating a model in C-, using ASP.NET Core, and deserializing JSON data. Understand the steps involved and solve common issues.
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This video is based on the question https://stackoverflow.com/q/74771175/ asked by the user 'FF7Lawrence' ( https://stackoverflow.com/u/20756345/ ) and on the answer https://stackoverflow.com/a/74771701/ provided by the user 'Dyles' ( https://stackoverflow.com/u/20756616/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: How to create new model and serialise json into it

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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How to Create a New Model and Deserialize JSON into It in C-

If you're new to C- and working with ASP.NET Core, you might find yourself grappling with how to effectively create models and convert JSON data into these models. This guide addresses the issue of converting data from a JSON file into a custom model you can use within your application. We will break down the process into simple steps to help you understand how to accomplish this task with ease.

Understanding the Problem

You have a JSON file named ResponseExample.json and a corresponding model called ResponseModel. Your goal is to read the JSON data from the file and populate your model with that data so you can utilize it in your Razor view pages. However, you've encountered a problem with deserializing the JSON correctly into your model.

Key Issues:

Improper instantiation of the ResponseModel

Incorrect deserialization of JSON data

Step-by-Step Solution

Let’s walk through the solution to properly create an instance of your model and deserialize the JSON data.

1. Load the JSON File

You need a method to read the JSON data from your file. Here's how you can do it using StreamReader:

[[See Video to Reveal this Text or Code Snippet]]

This method reads the contents of ResponseExample.json and returns it as a string, which will be useful in the next step.

2. Deserialize JSON into Your Model

Next, the JSON data needs to be converted into an instance of your model using deserialization. Be cautious about how you instantiate the model. If there’s a constructor defined within your ResponseModel, the default new keyword cannot be used properly. Instead, use the following approach:

[[See Video to Reveal this Text or Code Snippet]]

This line of code uses JsonConvert.DeserializeObject<T> to populate responseModel with the data from your JSON string. Make sure you assign responseModel correctly to your session or wherever needed in your application.

3. Set the Session Data

To make the deserialized ResponseModel accessible throughout your application, you'll want to store it in session variables with the following line of code:

[[See Video to Reveal this Text or Code Snippet]]

This ensures that the data is available for use across different pages in your application.

Conclusion

By following the steps outlined above, you should be able to effectively load JSON data into your C- application and interact with it through models. If you encountered issues with model instantiation or deserialization, adjusting your approach as described can help alleviate those problems.

If you have any questions or need further assistance on this topic, feel free to leave a comment below or reach out. Happy coding!

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