Class 10 Maths | Basic Proportionality Theorem | Prove BD/DC = BA/AC | Chapter 6 Important 5-Mark

Описание: Class 10 Maths | Basic Proportionality Theorem | Prove BD/DC = BA/AC | Chapter 6 Important 5-Mark Question

In ΔABC, AD is the angle bisector of ∠A.BA is produced to E such that CE ∥ AD. Prove that BD/DC=BA/AC

Description:
Unlock the complete explanation of one of the most important Class 10 Maths questions from Chapter 6: Triangles.
In this video, we solve a 5-mark CBSE Board question based on:

✔ Basic Proportionality Theorem (BPT)
✔ Angle Bisector Theorem
✔ Application in ΔABC to prove BD/DC = BA/AC

Using the diagram where AD is the angle bisector of ∠A and BA is extended to E such that CE ∥ AD.

This video gives a step-by-step, easy-to-understand proof perfect for:
✔ CBSE Class 10 Board Exam Preparation
✔ NCERT Chapter 6 Triangles
✔ Important 5-Mark Questions
✔ PYQs (Previous Year Questions)
✔ Students wanting full marks in geometry

🧠 What You Will Learn in This Video
Basic Proportionality Theorem statement
How to use BPT in real problems
How angle bisector theorem helps in triangles
How CE ∥ AD creates similar triangles
Complete proof of BD/DC = BA/AC
Perfect exam presentation method
Tips to avoid common mistakes

📘 Chapter Details
NCERT Class 10 Maths
Chapter 6 – Triangles
Related Theorems:
Basic Proportionality Theorem (Thales’ Theorem)
Angle Bisector Theorem
Similarity of Triangles


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