4 Reverse Linked List in Groups of K | Correct Edge Case Handling | Java DSA | Divya Explains
Автор: Divya Explains - Code & Consciousness
Загружено: 2026-01-12
Просмотров: 4
Описание:
In this video, we solve one of the most commonly misunderstood Linked List problems:
👉 Reverse a Linked List in groups of K (Java)
We don’t just reverse nodes — we strictly follow the problem statement:
✔ Only groups of exactly K nodes are reversed
✔ Remaining nodes (less than K) are left untouched
This video covers:
• Clear problem breakdown
• Why leftover nodes must NOT be reversed
• The common mistake most tutorials make
• Correct recursive Java solution
• hasKNodes() check explained in depth
• Dry run for k = 3
• Interview-ready explanation
Example:
Input:
1 → 2 → 3 → 4 → 5 → 6 → 7 → 8, k = 3
Output:
3 → 2 → 1 → 6 → 5 → 4 → 7 → 8
If you are preparing for:
✔ DSA interviews
✔ Java placements
✔ Linked List mastery
✔ FAANG / product-based companies
This video will fix your understanding permanently.
📌 Language: Java
📌 Topic: Linked List | Recursion | Pointer Manipulation
📌 Subscribe & follow the playlist to build DSA the right way — from the system level.
• DSA with Java
📌Chapters
00:00 - Problem Statement
00:42 - The 3-Pointer Strategy (prev, curr, next)
01:14 - Creating the Node Class
01:23 - reverseK() Function Logic
10:16 - hasKNodes() Function Logic
11:09 - Full Code - Node definition
11:23 - Full Code - hasKNodes() Function
11:34 - Full Code - reverseK() Function
14:23 - Full Code - printList() Function
14:43 - Full Code - main() Method
15:21 - Dry Run (k=3)
15:25 - Outro
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