Vectors and 3D Geometry Problems Solving - 2 | Class 12 , JEE Maths | Rohit Ranjan (IIT KGP)

Описание: In this video, we solve an important Class 12 Vectors & 3D Geometry problem involving a line that is perpendicular to two given lines in space.

👉 Problem Statement
Find the equation of a line passing through the point (1, 2, −4) and perpendicular to both the given lines:
L1: r = (8i -19j + 10k) + λ(3i − 16j + 7k) and L2: r = (15i+ 29j​+ 5k) + μ(3i + 8j - 5k)

🔍 Concepts Used
✔ Direction vectors of lines in vector form
✔ Cross product to find a direction perpendicular to both lines
✔ Equation of a line passing through a given point
✔ Vector and Cartesian forms of a line
This problem is solved step by step, focusing on:
Correct identification of direction vectors


Geometric meaning of perpendicularity in 3D


Board-exam friendly presentation and clarity



🎯 Who Should Watch This Video?
Class 12 CBSE / ISC students


Students preparing for board exams


Learners strengthening vector and 3D geometry fundamentals


This video is part of the Vectors & 3D Geometry Problem-Solving Playlist, created specially for Class 12 board exam preparation.

✅ SEO Tags (Comma-Separated)
vectors and 3d geometry class 12, perpendicular line in 3d, equation of line in 3d geometry, line perpendicular to two lines, vectors class 12 problems, 3d geometry problem solving, CBSE class 12 vectors, CBSE class 12 3d geometry, cross product application, direction vector of line, vector form of line equation, line through a point 3d, board exam vectors maths, ncert vectors and 3d geometry, class 12 maths vectors numericals, perpendicular direction using cross product, coordinate geometry in 3d, vector algebra class 12, line in space problems, maths class 12 3d geometry