53 Important Topics & PYQs | Unavoidable | Full Concept, Not Just Solutions | JEE Main

Описание: 📌 [ Unpaid Physics | Video 53 ]

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✅Complete Topic-Wise Discussion & Solution of JEE Main PYQs (till 2025)
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📌 CHAPTER DETAILS
Chapter: [ Error , Measurement & Expemental Physics ]
Topic: [ Screw Gauge | Least Count]

📌 PYQs DISCUSSED IN THIS VIDEO
(No. of PYQs: 4)
00:00 Intro
2:35 Theory
7:39
The least count of a screw guage is 0.01 mm. If the pitch is increased by 75% and number of divisions on the circular scale is reduced by 50%, the new least count will be x 10 mm.

#unpaidphysics

JEE M 24 Jan 2025 I
10:10
If the screw on a screw-gauge is given six rotations, if moves by 3 mm on the main scale. If there are 50 divisions on the circular scale the least count of the screw gauge is:

#unpaidphysics

JEE M 2020 Jan 9 (1)

(a) 0.001 cm

(b) 0.02 mm.

(c) 0.01 cm

(d) 0.001 mm.
11:23
Assertion A: If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm.

Reason R: Least count = Pitch Total divisions on circular scale In the light of the above statements, choose the most appropriate answer from the options given below:

#unpaidphysics JEE M 2021 July 27 (1)

(a) A is not correct but R is correct.

(b) Both A and R are correct and R is the correct explanation of A.

(c) A is correct but R is not correct.

(d) Both A and R are correct and R is NOT the correct explanation of A.
13:10
The least count of the main scale of a screw gauge is 1 mm. The minimum number of divisions on its circular scale required to measure 5 um diameter of a wire is:

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JEE M 2019 Jan 12 (1)

(a) 50

(b) 200

(c) 100

(d) 500