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Efficiently Search and Compare Dictionary Values in Python

Python search and compare Dict-values (coordinates-list) to a list (bbox) and return specific key

python

list

loops

dictionary

compare

Автор: vlogize

Загружено: 2025-05-27

Просмотров: 1

Описание: Discover how to `compare coordinates` in Python by checking if a bounding box fits within given coordinate ranges using dictionaries. Learn how to implement this with clear, structured code examples.
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This video is based on the question https://stackoverflow.com/q/69670598/ asked by the user 'beauvery' ( https://stackoverflow.com/u/17215350/ ) and on the answer https://stackoverflow.com/a/69670944/ provided by the user 'ferdy' ( https://stackoverflow.com/u/17197068/ ) at 'Stack Overflow' website. Thanks to these great users and Stackexchange community for their contributions.

Visit these links for original content and any more details, such as alternate solutions, latest updates/developments on topic, comments, revision history etc. For example, the original title of the Question was: Python search and compare Dict-values (coordinates-list) to a list (bbox) and return specific key

Also, Content (except music) licensed under CC BY-SA https://meta.stackexchange.com/help/l...
The original Question post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license, and the original Answer post is licensed under the 'CC BY-SA 4.0' ( https://creativecommons.org/licenses/... ) license.

If anything seems off to you, please feel free to write me at vlogize [AT] gmail [DOT] com.
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Introduction

In the world of Python programming, working with dictionaries and lists is a fundamental skill that can unlock a wide range of possibilities. Sometimes, you might need to determine if specific coordinates (represented as a bounding box) fit within the ranges defined by those in a dictionary. In this post, we'll tackle this very problem: comparing a list of bounding box coordinates against those stored in a dictionary and returning the corresponding keys.

Let’s delve into how to efficiently implement this solution step by step.

Understanding the Problem

We start with a dictionary of coordinates organized in a list, known as co_list:

[[See Video to Reveal this Text or Code Snippet]]

Each entry contains a set of coordinates with the format [cx1, cx2, cy1, cy2]. From user input, we also have a list of bounding box coordinates (bb_list):

[[See Video to Reveal this Text or Code Snippet]]

Our goal is to check if any part of the bounding box fits within the coordinate ranges provided in co_list. Specifically, we want to check if the bottom-left corner (bx1, by1) or the upper-right corner (bx2, by2) falls within the bounds set by each coordinate pair in the dictionary.

Breaking Down the Solution

Step 1: Setup the Loop

We will iterate through each item in co_list and then through each dictionary key-value pair to extract the coordinates for comparison.

Step 2: Define the Coordinates

For easier reference, let’s define the coordinates we are working with:

cx1, cx2 - x-coordinates from co_list

cy1, cy2 - y-coordinates from co_list

bx1, by1, bx2, by2 - coordinates from bb_list

Step 3: Implement the Condition to Compare Coordinates

Now, we need to write the condition that checks if either corner of bb_list fits within the ranges of any of the entries in co_list.

Example Code Implementation

Here’s how the full implementation looks in Python:

[[See Video to Reveal this Text or Code Snippet]]

Expected Output

If you run the code above, it will produce the following output:

[[See Video to Reveal this Text or Code Snippet]]

This result indicates that both entries in co_list satisfy our criteria for bounding boxes.

Conclusion

By breaking down the problem and implementing a structured approach, we demonstrated how to effectively search and compare dictionary values in Python. This method not only allows for clear understanding but also promotes scalability in handling larger datasets moving forward.

Remember, grasping dictionary and list manipulations is pivotal for enhancing your skills in Python programming. Try to experiment with variations of this problem to solidify your understanding!

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