Rakesh Dubey
Hello....
Dear Students and Respected Viewers....!
Myself Rakesh Dubey, love to learn and teach Mathematics.
I am a Mathematics Teacher by Profession and have been teaching for more than Quarter of a Century :)
On this YouTube Channel you will find different Competitive exam Math problems like IIT-JEE, RMO, INMO, CAT, SAT, NTSE and many more Competitive Exams
Requesting you all to Support my Channel.
Thank you...!!
A Tricky area problem.|| Find the area of the quadrilateral ABCD. | ∠B + ∠C = 270° || Right Triangle
Find the shaded ∆'s area. || Square ||Rectangle || Ar. of similar ∆s ||Triangles with Common vertex.
Find ∠ BAC. || ∠ OPB = 112°. || Externally touching circles || Common Tangent. ||10th grade problem.
Find ∠CEB. Angle chasing problem.|| Square and Semicircle.|| Tangent.|| 90° || Alternate segment.
To find the shaded portion's area.|| Inscribed square of side length √10 cm.|| Quadrant. (π = 3.14)
●To find the shaded portion's area.| Geometry |●| Quadrant |●| Circle || Arc || Square || Right ∆.||
Solve for real values of x, y and z. || Olympiad Math || Theory of Equations || INMO || RMO ||
Find ∠ BAC. || Angle Chasing.|| ∠BAE = ∠ADC.|| BE : EC = 2 : 1. || Triangles with common vertex.
BD² + BE² + BF² = ? | CAT || Geometry || Stewart's Theorem || Apollonius's Theorem || Pythagoras .
Geometry Quiz. || The area of smaller circle : The area of eqi.∆ABC = ? || Incentre || Circumcente.
Find (p + q + r).|| ∆ACB is a right angled ∆ with ∠C =90°.|AB = 4, CP=1 ||AP/BP = p + q√r.| Geometry
AC/AT= ?? ABCD is a parallelogram | AP : AB = 13 : 118; AQ : AD = 13 : 142.| Geometry | Similarity
Find a : b : c. || Median BD is trisected by inscribed circle. || Stewart Theorem.|| Tangent.||
Find ∠QPS.|| Angle chasing problem || 9th grade Geometry || Circle || Tangents.|| Isosceles ∆.
Find the blue shaded ∆'s area. ABCDEF is a regular hexagon of side length 2√3 units.|| Equal Squares
Find the area of equilateral ∆ DEF.||Right angled Isosceles ∆ with hypotenuse = 4 cm.|| Trigonometry
Find (a + b). || Isosceles ∆. || Altitude AM = 11. || AD = 10. || ∠BDC = 3∠BAC. Perimeter = a + √b.
Find the area of the shaded semicircle. || Quadrant's radius = 56√2 cm.|| Equal Intercept Theorem.
Find the length of the rectangle. || Geometry Semicircle || Isosceles ∆. || Cyclic quadrilateral.
How to find the unknown shaded area..?? | Square || Geometry || Isosceles ∆. || Pythagorean Theorem.
Find y : x || Orange area : Green area = ?? | Quadrant | Semicircle. | Length of rectangle = 8 units
Find ∠ BAD (Using Pure Geometry). ABC is an Isosceles ∆. AB = AC. ||∠DBC = 10°. || ∠ACD = 20°.
ICSE (10th) Mathematics Exam-2023.|| Section-(B) Solutions.|| Construction.|| Ogive || Histogram.
ICSE (10th) Mathematics exam-2023 || Section-(A) Questions and solutions.
Find the area of the rectangle AEFG.|| Area of two touching circles are 8π and 2π cm².|| Geometry.
Find the area of the ring.|| Area of the square ABCD = 200 cm². AP = PC.|| Geometry || Mensuration.
Find the area of square ADTP .|| AT touches the circle at T. Diameter AB = 20 cm. || Interesting..!!
Find the shaded area. ABDC is a trapezoid || BD = 10 cm, DC = 8 cm, AC = 4 cm. || ∠D = ∠C = 90°.
Find the radius of bigger circle. || R₁ = 9 cm ; R₂ = 16 cm ; Tangents are parallel, i.e. l₁∥ l₂.
Find the area of ∆ without square.|| Area of semicircles = 4 & 9 sq.units || ∆ BAC is a right ∆.